In scenario X, a device that can measure the volume of sound is placed on the ground in vacuum. An object, also in vacuum, is released from rest above the ground and falls so that it strikes the ground next to the device. In scenario Y, the experiment is repeated in the same way, except the device and object are not in vacuum. In terms of energy transfer, which of the following claims is correct about the volume of sound produced by the object when it hits the ground in scenario X and scenario Y? a. The measured volume in scenario X is greater than in scenario Y, because sound waves are not impeded by particles in the air as they travel through vacuum. Thus, the sound waves have more energy in scenario X than in scenario Y.
b. The measured volume in scenario X is less than in scenario Y, because sound waves must have a medium to transfer energy. Thus, the sound waves have more energy in scenario X than in scenario Y.
c. The measured volume in scenario X is the same as in scenario Y, because the experiment is identical in both scenarios except for the amount of air where the experiments are conducted. Thus, the sound waves have equal energies.
d. The answer cannot be determined, because the recorded volume of sound is not related to the energy contained within the sound wave.

the correct answer is B

Explanation:

Mechanical waves need a material medium that supports them for their transmission, sound is a material wave that is transmitted by the longitudinal vibrations of material media, one of the media through which sound is transmitted is air, but if it is in contact with other media, water, wood, metal, etc., it can also be transmitted by these means.

In this experiment for case X, sound is transmitted through the floor, but since there is no air, it cannot be transmitted

In experiment Y, sound is transmitted through the floor and through the air, therefore, having two transmission media, the energy captured by the sensor must be greater in this experiment.

when examining the answers the correct one is B

no

sodium is solid at rt

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .