A 1500 kg car traveling to the north is slowed down uniformly from initial velocity of 20 m/s by a 6000 N braking force acting opposite the car's motion. What is the car's velocity after 2.00 s?

12 m/s

Explanation:

Given data

Mass m= 1500kg

intitial velocity u= 20m/s

force F= 6000N

time t= 2 seconds

Required

The final velocity v

From

Ft= mΔv

Ft= m(u-v)

substitute

6000*2= 1500(20-v)

solve for v

12000= 30000- 1500v

collect like terms

12000-30000= -1500v

-18000= -1500v

divide both sides by  -1500v

v= 18000/1500

v=12 m/s

Hence the velccity is 12 m/s

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