Hi. I need help with this question :

A piece of copper of mass 40g at 200°C is placed in a copper calorimeter of mass 60g containing 50g of water at 25°C. Ignoring heat losses, what will be the final temperature of the mixture.
(Specific heat capacity of copper= 0.4J/g/K, specific heat capacity of water= 4.2J/g/K )?

Please show workings.

Let the final temperature be "T".

For the piece of copper :

Then the heat of copper :

For copper calorimeter :

Then the heat of copper calorimeter :

For water :

Then heat of water :

By energy conservation, the sum of all these energies should be zero as there were no heat energy change before the process, i.e.,

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[Note: in case of considering temperature difference it's not required to convert the temperatures from to K or K to .]

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