Ellie is shooting a free throw. At the instant the ball leaves her hand the ball is traveling at a velocity of 9 m/sec, at an angle above the horizontal of 29.5 degrees. If you are standing beneath the basketball rim, videotaping, you can only see the vertical motion of the ball, since its horizontal motion is straight towards you. What is the magnitude of the ball's initial vertical velocity (if you measured it using your video data, in m/sec)

Vy = 4.43 m/s

Explanation:

given data

velocity = 9 m/sec

angle horizontal = 29.5 degrees

solution

we get here ball initial vertical velocity will be here

Vy = v sinθ       1

put here value and we get

Vy = 9 × sin(29.5 )  

Vy = 4.43 m/s

i don't know that i agree with that but what's the question ?

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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