A200-n sled of slides down a frictionless hillside that rises at 37â° above the horizontal. what is the magnitude of the force that the surface of the hill exerts on the sled?

159.72 N

Explanation:

The magnitude of the force that the surface of the hill exerts on the sled is equal to the normal reaction.

N = m g cos θ

Given:

m g = 200 N

θ = 37°

N = (200 N) (cos 37°) = 159.72 N

Thus, the surface of the hill exerts 159.72 N force on the sled.

answer: cesare beccaria developed the classical school of criminology with from philosopher jeremy bentham

explanation:

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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