Compute the work (in joules) required to compress a spring 3 cm more when it is already compressed 5 cm, assuming that the spring constant is =160 N/m.

7×160=1120kj so,1120kj=1.12j.

Explanation:

Energy is equal to force times distance,so we add all the distance and we multiply them with the total force of the spring to get the answer. However, the answer is in kilojoules so we have to change it in to joules by dividing the answer into joules by 1000..

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

i need with 1.3.2 investigate cycling o2 and co2 apex

we need to see it