A 60-kg skate boarder is standing on his stationary board. A bigger, out of control 75-kg skate boarder crashes into him with a velocity of 4 m/s. Their boards get stuck together in this inelastic collision. How fast are the moving after the collision?

2.22m/s

Explanation:

Given parameters:

M1  = 60kg

M2  = 75kg

V1  = 0m/s

V2  = 4m/s

Unknown;

Velocity after collision  = ?

Solution:

To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;

     M1 V1  + M2 V2  = v(M1 + M2)

So;

       60 x 0  +  75 x 4  = v (60 +75)

                 300  = 135v

                   v = 2.22m/s

this is a good question! i'll do some research and come back when i have the answer!

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2