Jack and Nas decided to have a race from their houses to the park to know who runs the fastest. Jack whose house is 15 kilometers away from the park finished the race in 2 hours while Nas finished in 1.5 hours from a distance of 10 kilometers from the park. What is Jack's speed with unit of measure also And what is Nas's speed also with the unit of measure i dont know if this is physics its just science because i cant find science

the Jack speed is greater than the Nas speed  

   v₁ = 2.08 m / s >  v2 = 1.85 m / s

Explanation:

For this exercise we can find the average speed of each of the boys, the average speed is defined as the displacement in the time interval

          v = x / t

Jack.

It tells us that it travels x = 15 km in a time of t = 2 h

let's reduce the magnitudes to the SI system

     x = 15 km (1000 m / 1 km) = 15 10³ m

     t = 2 h (3600 s / 1 h) = 7200 s

let's calculate

     v₁ = 15 10³/7200

     v₁ = 2.08 m / s

Nas travels a distance of x = 10 km in a time of t = 1.5 h

      x = 10 km = 10 10³ m

      t = 1.5 h (3600s / 1h) = 5400 s

let's calculate the speed

     v2 = 10 10³/5400

      v2 = 1.85 m / s

From these results we can see that the Jack speed is greater than the Nas speed

v=ir = 3x15 =45 v