Determine the final velocity of a proton that has an initial velocity of 2.35 x 10^5 m/s and then is accelerated uniformly in an electric field at a rate of –1.10 x 10^12 m/s/s for 1.50 x 10^-7 s. a 7.00 x 10 ^ 3 m/s
b 7.00 x 10 ^ 4 m/s
c 7.00 x 10 ^ 5 m/s
d 7.00 x 10 ^ 6 m/s

b. 7.0 x 10⁴ m/s

Explanation:

Acceleration is defined as the rate of change of velocity with time.

a= v₂-v₁ / t

a= -1.10 x 10¹² m/s²    

v₁ = 2.35 x 10⁵ m/s

v₂ = ?

t= 1.50 x 10⁻⁷ s

Applying the values to the equation

a=v₂-v₁ / t

-1.10 x 10¹² =v₂ - 2.35 x 10⁵ / 1.50 x 10⁻⁷

-1.10 x 10¹² * 1.50 x 10⁻⁷ = v₂ - 2.35 x 10⁵

-1.65 x 10⁻⁵ = v₂ - 2.35 x 10⁵

-1.65 x 10⁻⁵ + 2.35 x 10⁵ = v₂

7.0 x 10⁴ m/s = v₂

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.