A ball is rolling with a constant acceleration of 13 m/s starting from rest. How long will it take to increase its velocity to a final speed of 62 m/s?

Time taken : 4.77 s

Given

a = 13 m/s²

vf = final velocity = 62 m/s

Required

time taken

Solution

An equation of uniformly accelerated motion  

vf = vo + at  

vf² = vo² + 2a (x-xo)  

x = distance on t  

vo / vi = initial speed  

vt / vf = speed on t / final speed  

a = acceleration  

Input the value :

vo =0 ⇒from rest

vf=at

62 m/s = 13 m/s².t

t = 62 : 13

t = 4.77 s

i would say the answer is food.

hope this !

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2