Two astronauts, each having a mass of 75.0kg are connected by a 10.00m rope of negligible mass. They are isolated in space, moving in circle around the point halfway between them at a speed of 5.00m/s. Treating the astronauts as particles. calculate a) Their new speeds
b)The New rotational energy of the system.

divide the right side by the left side

0.024÷1.2=0.02 for example

it is easily magnetized.

truck y has a greater velocity than truck x.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j