Physics, 08.02.2021 04:50 Tyrant4life
Please Help! I need to turn this in ASAP. I can’t find the answer... If you could show the work it would be very very appreciated!
(Part 1)
A merry-go-round rotates at the rate of 0.4 rev/s with an 99 kg man standing at a point 2.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 1 m from the center? Consider the merry-go-round is a solid 73 kg cylinder of radius of 2.5 m. Answer in units of rad/s.
(Part 2)
What is the change in kinetic energy due to this movement? Answer in units of J.
Answers: 2
Physics, 22.06.2019 16:00
The process of predicting values that extend beyond the range of data points is called absolute value extrapolation interpolation prediction for any given: )
Answers: 2
Physics, 23.06.2019 01:30
The field lines around one end of a bar magnet are shown below based on the diagram, what can you conclude about the pole of the magnet? a.is a south pole because the field hnes spread out from this end b.a north pole because the field lines spread out from this end c.a nouth pole because the field lines enter the magnet at this end d.is a north pole because the field lines enter the magnet at this end
Answers: 1
Physics, 23.06.2019 01:30
Acyclotron is used to produce a beam of high-energy deuterons that then collide with a target to produce radioactive isotopes for a medical procedure. deuterons are nuclei of deuterium, an isotope of hydrogen, consisting of one neutron and one proton, with total mass 3.34×10−27kg. the deuterons exit the cyclotron with a kinetic energy of 6.40 mev .a-what is the speed of the deuterons when they exit? b-if the magnetic field inside the cyclotron is 1.25 t, what is the diameter of the deuterons' largest orbit, just before they exit? c-if the beam current is 350 μa how many deuterons strike the target each second?
Answers: 3
Physics, 23.06.2019 03:30
Use the ratio form of kepler’s third law, = , and the data provided to determine the time it takes mars to orbit the sun. round your answer to the nearest tenth. earth’s orbital period = 1.0 earth year earth’s distance from the sun = 1.0 au mars’s distance from the sun = 1.5 au it takes mars about ⇒ 1.8 earth years to orbit the sun.
Answers: 2
Please Help! I need to turn this in ASAP. I can’t find the answer... If you could show the work it w...
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