Determine the magnitude of the gravitational force (in nano-Newton's, i. e. 10^-9N) between a 61.6 kg girl and a 71.2 kg boy standing 95 m apart from one another.

3.24×10¯² nN

Explanation:

From the question given above, the following data were obtained:

Mass of girl (M₁) = 61.6 kg

Mass of boy (M₂) = 71.2 kg

Distance apart (r) = 95 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force (F) =?

The force of attraction between the girl and the boy can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 61.6 × 71.2 / 95²

F = 6.67×10¯¹¹ × 61.6 × 71.2 / 9025

F = 3.24×10¯¹¹ N

Finally, we shall convert 3.24×10¯¹¹ N to nN. This can be obtained as follow:

1 N = 10⁹ nN

Therefore,

3.24×10¯¹¹ N = 3.24×10¯¹¹ N × 10⁹ nN / 1 N

3.24×10¯¹¹ N = 3.24×10¯² nN

Thus, the force attraction between the girl and the boy is 3.24×10¯² nN

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.