Physics, 09.02.2021 02:00 allakhalilpea0zc

A point charge q1 = -8.9 μC is located at the center of a thick conducting shell of inner radius a = 2.8 cm and outer radius b = 4.1 cm, The conducting shell has a net charge of q2 = 2.2 μC. 1)What is Ex(P), the value of the x-component of the electric field at point P, located a distance 8.5 cm along the x-axis from q1?N/C.

2)What is Ey(P), the value of the y-component of the electric field at point P, located a distance 8.5 cm along the x-axis from q1?0N/C.

3)What is Ey(P), the value of the y-component of the electric field at point P, located a distance 8.5 cm along the x-axis from q1?N/C

4)What is Ey(R), the value of the y-component of the electric field at point R, located a distance 1.4 cm along the y-axis from q1?N/C

5)What is σb, the surface charge density at the outer edge of the shell?___C/m2

6)What is σa, the surface charge density at the inner edge of the shell?C/m2

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Answer from: annapittbull12

1) Ex(P) = -8.34602 N/C

2) E_y(P) = -5.23850174216 N/C

3) Question (3) is a similar question to (1)

4) E_y(P) = -5.23850174216 N/C

5) $\sigma _b$ ≈ 1.041466 C/m²

6) σₐ ≈ 2.2330413 C/m²

Explanation:

The given parameter of the point charge located at the center of a conducting shell

The charge of the point charge, q₁ = -8.9 μC

The inner radius of the shell, a = 2.8 cm

The outer radius of the shell, b = 4.1 cm

The charge of the conducting shell, q₂ = 2.2 μC

Therefore, we have;

1) The point P(8.5, 0)

$V = k \cdot \dfrac{q_1 + q_2 }{r^2}$

By plugging in the values, we have;

For

R₁ < R₂ < r, for the electric field at the point, 'P', we have;

$E_x(P) = 9 \times 10^9 \times \dfrac{-8.9 \ \times 10^{-6} + 2.2 \ \times 10 ^{-6} }{(0.085 \ )^2} = -8.34602$

Ex(P) = -8.34602 N/C

2) For the point given with coordinates (8.5, 0), the distance of the y-component of point from the center = 0

The y-component of the electric field = 0 N/C

4) For r = 1.4 cm, along the y-axis we have;

R₁ < r < R₂

Therefore, we have;

$E = k \cdot \left( \dfrac{q_1 }{r} + \dfrac{q_2}{R_2}\right)$

Substituting the values, we get;

$E_y(P) = 9 \times 10^9 \times \left( \dfrac{-8.9 \times 10^{-6}}{0.014} + \dfrac{2.2 \times 10^{-6}}{0.041}\right) = -523850174216$

E_y(P) = -5.23850174216 N/C

5) The charge density, $\sigma _b$ , is given as follows;

$\sigma_b = \dfrac{Q}{A} = \dfrac{2.2 \times 10^{-6} }{4\times \pi \times 0.041^2 } \approx 1.041466 \ C/m^2$

6) Similarly, we have;

$\sigma_a = \dfrac{Q}{A_a} = \dfrac{2.2 \times 10^{-6} }{4\times \pi \times 0.028^2 } \approx 2.2330413 \ C/m^2$

Answer from: Quest

the answer is b i think

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

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