The specific heat of water is 4,186 J/kg.'C. Approximately how much heat must be removed from 0.500 kg of water to change its temperature from 24.0°C to
5.00°C?

yes

Explanation:

Explanation:

Q= mc∆T

∆T= 5-24=- 19

Q= 0.5*4186*-19

Q= -39767 J

negative sign show heat releases

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.