Ablock of mass m = 15.0 kg is suspended at rest by two strings attached to walls, as shown in the figure. the left string is horizontal and the right string makes an angle _ = 50.0á with the horizontal. what is the tension in the left string? (assume the ring where the strings come together is massless.)

Forces that appear in the free body diagram

1) T2: horizontal tension to the left

2) T1: tension to the right, making angle 50° with the horizontal

     Vertiical component of T1: T1y = T1*sin(50°)
     Horizontal component of T1 = T1x = T1. cos(50°)

3) Weight of the mass: 50 kg * 9.8 m/s^2 = 490 N

4) Equilibrium analysis

Net vertical forces = 0 => T1y = weight => T1*sin(50°) = 490 N => T1 = 490 N / sin (50°) = 639.7 N

T1 = 639.7 N

Net horizontal forces = 0 => T2 = T1x = T1*cos (50°) = 639.7 N * cos(50°) = 411.2 N

411.2 N

Does this your question?