‼️‼️EMERGENCY ITS DUE SOON‼️‼️ A box weighing 2000N is sliding across a cement floor. The force pushing the box is 500N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box? 

1.96m/s^2

Explanation:

According to Newtons second law;

F = ma

a = F/m

a = nR/m

a = nmg/m

a = ng

n is he coefficient of friction = 0.2

g  = 9.8m/s^2

a = 0.2 * 9.8

a = 1.96m/s^2

Hence the acceleration of the box is 1.96m/s^2

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)