Three resistors are connected in series with each other. R1= 19 ohms, R2= 20 ohms and R3= 5 ohms. Find the following if the battery is 60 v.

Rt

It

I1

I2

I3

V1

V2

V3

Power

Make them both to where they have the denominator of 18that makes 3/2 equal 27/18 and 1/9 equal 2/18so now you have  27/18x+5=2/18subtract 5 from the other sideso now you have 27/18x+2/18-5then subtract 2/18 from 27/18 to get 25/18x=-5then divide 25/18 by -5 and your answer will be  -5/18

//(b) both involve the use of levers;

Hello,the answers iron,  hope this