Physics, 15.02.2021 16:30 jjbossgt

The distance x of a particle moving in one dimension, under the action of a constant force is related to time is given by the equation t = 2x +1+3 . where x is in metres and
in seconds. Find the displacement of the particle when its velocity is zero. PLEASE SOLVE

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Answer from: booherc78

0 m

Explanation:

The question is incomplete, the complete question is attached.

Solution:

Velocity is the rate of change of displacement with respect to time. It is the ratio of change in displacement to change in time.

Give that the displacement x is given by the equation:

$t=\sqrt{x}+3\\\\\sqrt{x} =t-3\\\\squaring\ both\ sides\ to\ get:\\\\(\sqrt{x}) ^2 =(t-3)^2\\\\x=t^2-6t+9\\\\The\ velocity\ v=\frac{dx}{dt} ;differentiating \ through\ with\ respect\ to\ t:\\\\\frac{dx}{dt} =\frac{d}{dt} (t^2-6t+9)\\\\v=2t-6\\\\At\ v=0:\\\\0=2t-6\\\\2t=6\\\\t=3\ s\\\\substitute\ t=3\ in \ x=t^2-6t+9\ to\ find\ displacement:\\\\x=3^2-6(3)+9\\\\x=0\ m$

The distance x of a particle moving in one dimension, under the action of a constant

force is relat

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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