1. Faça as transformações: a) 0,5 h = s h) 20 cm = m
b) 2,0 h = s i) 5,0 kg = g
c) 3,5 h = s j) 1,5 kg = g
d) 1/4 h = s k) 450,0 g = kg
e) 3,0 m = cm l) 20,0 g = kg
f) 2,5 m = cm m) 500,0 g = kg
g) 0,5 m = mm n) 1000,0 g = kg

1. a) 0.5 h = 1,800 s

  h) 20 cm = 0.2 m

  b) 2.0 h = 7,200 s

   i) 5.0 kg = 5,000 g

  c) 3.5 h = 12,600 s

  j) 1.5 kg = 1,500 g

  d) 1/4 h = 900 s

  k) 450.0 g = 0.45 kg

  e) 3.0 m = 300 cm

   l) 20.0 g = 0.02 kg

  f) 2.5 m = 250 cm

  m) 500.0 g = 0.5 kg

   g) 0.5 m = 500 mm

   n) 1000.0 g = 1 kg

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s