When a potential V is applied across a capacitor, a charge q is stored. What charge is stored if the potential across the capacitor is halved

q' = 0.5q

Hence, the charge stored is also halved

Explanation:

The capacitance of a capacitor is given by the following formula:

------- eqn(1)

where,

C = Capacitance of the capacitor

q = charge stored in the capacitor

V = potential across the capacitor

Now, if we make potential half of its initial value:

q' = 0.5q

Hence, the charge stored is also halved

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6