Need help only in part C! An electric space heater draws 15.0 A from a 120-V source. It is operated, on the average, for 5.0 h each day. a. How much power does the heater use ? b. How much energy in kWh does it consume in 30 days? C. AED 0.30 per kWh , how much does it cost to operate the heater for 30 days ?

A. 1800 Watt

B. 10.8 KW/h

C. AED 3.24

Explanation:

A. Determination of the power.

Voltage (V) = 120 V

Current (I) = 15 A

Power (P) =?

P = IV

P = 15 × 120

P = 1800 Watt

B. Determination of the energy consumption in KW/h for 30 days

We'll begin by converting 1800 Watt to kilowatt. This can be obtained as follow:

1000 W = 1 KW

Therefore,

1800 W = 1800 W × 1 KW / 1000 W

1800 W = 1.8 KW

Next, we shall determine the energy consumption per day. This can be obtained as follow:

Power (P) = 1.8 KW

Time (t) = 5 hour per day

Energy (E) =?

E = P /t

E = 1.8 / 5

E = 0.36 KW/h per day.

Finally, we shall determine the energy consumption in 30 days. This can be obtained as follow:

1 day = 0.36 KW/h

Therefore,

30 days = 30 × 0.36 KW/h

30 days = 10.8 KW/h

Thus, the energy consumption in 30 days is 10.8 KW/h

C. Determination of the cost of operation in 30 days.

1 KW/h = AED 0.30

Therefore,

10.8 KW/h = 10.8 KW/h × AED 0.3 / 1 KW/h

10.8 KW/h = AED 3.24

Thus, the cost of operation in 30 days is AED 3.24

it was given as a lesson and guide for prayer.

technology is the application of the knowledge gained by science.