Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 570 N/C. If the particles are free to move, what are their speeds (in m/s) after 47.6 ns?

Explanation:

Given that,

Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 570 N/C.

We need to find their speeds after 47.6 ns.

For electron,

The electric force is given by :

Let a be the acceleration of the electron. So,

F = ma

m is mass of electron

Let v be the final velocity of the electron. So,

v = u +at

u = 0 (at rest)

So,

For proton,

Acceleration,

Now final velocity of the proton is given by :

Hence, this is the required solution.

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )