ucelena rolls a 7.0 kg bowling ball down the alley for the league championship. One pin is still standing, and Lucelena hits it head-on with a velocity of 9.0 m/s. The 2.0 kg pin acquires a forward velocity of 14.0 m/s. What is the final momentum of the bowling ball? Before the collision After the collision m1 = v1 = m2 = v2 = m1 * v1 + m2 * v2 p1 = m2 = v2 = p1 + m2 * v2 Elastic collision and isolated collision, we can apply the law of . So, I can say: