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Physics, 02.03.2021 14:00 GodlyGamer8239

An electron moves across Earth's equator at a speed of 2.5 x 10 m/s and in a direction 35° north of east. At this point, Earth's magnetic field has a direction due north, is parallel to the surface, and has a value of
0.10 x 10- T. What is the magnitude of the force acting on the electron due to its interaction with Earth's
magnetic field? (q.-1.60 x 10-19 C)

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