Please Help! ASAP! 1. A proton moves perpendicularly to a magnetic field that has a magnitude of 4.20 x 10-2 T. What is the speed of the particle if the magnitude of the magnetic force on it is 2.40 X 10–14 N?

2. If an electron in an electron beam experiences a downward force of 2.0 x 10-14 N while traveling in a magnetic field of 8.3 x 10-2 T west, what is the direction and magnitude of the velocity?

3. A uniform 1.5 T magnetic field points north. If an electron moves vertically downward (toward the ground) with a speed of 2.5 X 107 m/s through this field, what force (magnitude and direction) will act on it?​

10 is the . . .

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

I’m not sure about this question

Answer is  true.  because the sensory memory it can also have a fraction of a second before the information is lost. hope it .