Water of mass 100 g at a temperature of 100 °C is converted into steam at 100 °C. The specific latent heat of vaporisation of water is 2300 J/g.
How much thermal energy is absorbed by the water?
0 230 000
0 23 000 000 J
0 230 J
O 23 J

The thermal energy absorbed by the water is 230,000 J.

Explanation:

Given;

mass of the water, m = 100 g

The specific latent heat of vaporization of water, L = 2300 J/g

temperature of the steam, θ = 100 °C

The thermal heat capacity or thermal energy absorbed by the water is calculated as follows;

H = mL

H = 100g x 2300J/g

H = 230,000 J

Therefore, the thermal energy absorbed by the water is 230,000 J.

Therefore

learn it on the intertant so you can solve

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2