Please explain I am so confused on this At what distance would the repulsive force between two protons have a 2 points
magnitude of 2.00 N? Let the charge on a proton be e = 1.6 10^-19 C,
and let constant k = 8.99 X 10^9 Nm2/C2. *
A) 1.07 x 10^-14 m
B) 1.28 x 10^-38 m
C) 7.19 x 10^-10 m
D) 2.68 x 10^-4 m

(I think it is either A or B but I’m not sure)

An  atom  (ours, not carroll's) consists of a positively charged  nucleus, surrounded by one or more negatively charged particles called  electrons. the positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen. although the nucleus is heavy, it is quite small compared with the overall size of an atom. the radius of a typical atom is around 0.1 to 0.25 nanometres (nm), whereas the radius of a nucleus is about 10-6  nm.  *  if an atom were enlarged to the size of the earth, its nucleus would be only 200 feet in diameter and could easily rest inside a small football stadium.read more on -