Physics, 04.03.2021 18:50 sakurauchiha913
A 15 kg pitbull runs along a circular track of radius 5 m at a constant
speed of 11 m/s. Calculate the centripetal force acting on the pitbull. To
receive full credit, you must write the equation you are using, show what
you value with units that you are substituting for each variable, and state
your final answer in units.
Answers: 1
Physics, 22.06.2019 00:10
The energy released by a chemical reaction can be measured using a calorimeter. when barium hydroxide octahydrate crystals are reacted with dry ammonium chloride inside of a coffee cup calorimeter, the temperature of the 18.00 g of water in the calorimeter decreases from 30.0°c to 8.0°c. the equation for calculating energy absorbed or released by a reaction is: where q is the energy released or absorbed, m is the mass of water in the calorimeter, cp is the specific heat of water, and δt is the observed temperature change. if the specific heat of liquid water is 4.19 j/g·°c, how much energy was absorbed by the reaction?
Answers: 3
Physics, 22.06.2019 02:30
You are about to open a container of soy milk but notice that there are instructions to “shake well before serving.” the soy milk is most likely a
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Physics, 22.06.2019 06:40
Use the right-hand rule for magnetic force to determine the charge on the moving particle. this is a charge.
Answers: 1
Physics, 22.06.2019 16:30
Place several e-field sensors at a few points on different equipotential lines, and look at the relationship between the electric field and the equipotential lines. which statement is true? 1-at any point, the electric field is perpendicular to the equipotential line at that point, and it is directed toward lines of higher voltages. 2-at any point, the electric field is perpendicular to the equipotential line at that point, and it is directed toward lines of lower voltages. 3-at any point, the electric field is parallel to the equipotential line at that point.
Answers: 1
A 15 kg pitbull runs along a circular track of radius 5 m at a constant
speed of 11 m/s. Calculate...
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