Assuming that the driver of your car immediately takes his foot off the accelerator when he hits 27 m/s, what will be the kinetic energy of your car when it
comes to the base of the hill?

mass= 1429.786 kg

Answerboth technicians (a) and (b);

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.