A piece of paper floats though the air towards the ground. At one point, the air resistance (Fair) on the paper pushes up with 0.01 N of force. Force due to gravity (Fg) pulls the ball down with a force of 0.02 N.
Show your work

-0.01N

Explanation:

I'm assuming you're asking for the net force of the paper.

0.01N - 0.02N = -0.01N

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.