A 2-kg iron ball is swung in a horizontal circular path at the end of a 1.6-m length of
rope. Assume the rope is very nearly hori.
zontal and the ball's speed is 10 m/s. Calcu-
late the tension in the rope.

The tension  is:

Explanation:

We know that the centripetal force is:

And the tension will be equal to the centripetal force at this point, so we have:

a(c) is the centripetal acceleration.

v is the tangential speed (10 m/s)

R is the radius (1.6 m)

m is the mass of the ball (2 kg)

Therefore, the tension will be:

I hope it helps you!

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer