A cricket player hit a ball of mass 250 g moving with velocity of 6 m/sec. if ball move with a velocity of 9 m/sec in opposite direction. a. Calculate impulse of the system.
b. Deduce the force acting on it for 0.5 min

please someone answer

Explanation:

Given that,

Mass of a ball, m = 250 g = 0.25 kg

Initial velocity of the ball, u = 6 m/s

Final velocity of the ball, v = -9 m/s

(a) Impulse of the system is given by :

Impulse = change in momentum

J = m(v-u)

J = 0.25(-9-6)

= -3.75 kg-m/s

(b) Impulse = Ft

If t = 0.5 min = 30 s

So,

So, impulse of the system is -3.75 kg-m/s and the force is -0.125 N.

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

d is the correct answer