PLS ANSWER ASAP ILL APPRECIATE IT A LOT!!
please explain in details how u did do u could !!!

a) W = - 3387525.12 J = - 3.39 MJ

b) F = - 19031.04 N = - 19 KN

Explanation:

First, we need to find the deceleration of the rocket by using the third equation of motion:

where,

a = deceleration = ?

s = distance covered = 178 m

vf = final speed = 0 m/s

vi = 284 m/s

Therefore,

a = 226.56 m/s²

b)

Now, we can find the force by Newton's Second Law:

F = - 19031.04 N = - 19 KN

Here, negative sign shows braking force.

a)

For work done:

W = - 3387525.12 J = - 3.39 MJ

it breaks and dirupture other materials and other sencews from the bottom

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s