Physics, 08.03.2021 18:10 hannahhh565

Running with an initial velocity of +11m/s, a horse has an average acceleration of -1.81m/s 2 . How long does it take for the horse to decrease its velocity to 6.5m/s?

Answers: 2

Show answers

Answers

Answer from: ridzrana02

2.49 seconds

Explanation:

From the question,

a = (v-u)/t Equation 1

Where a = acceleration, v = final velocity, u = initial velocity, t = time

Make t the subject of the equation

t = (v-u)/a Equation 2

Given: v = 6.5 m/s, u = 11 m/s, a = -1.81 m/s²

Substitute these values into equation 2

t = (6.5-11)/(-1.81)

t = -4.5/-1.81

t = 2.49 s

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

Another question on Physics

Physics, 22.06.2019 05:30

If gases like carbon dioxide and methane make up less than 1% of the total atmosphere, why is it important for scientists to monitor changes in percentages of these gases?

Answers: 1

Answer

Physics, 22.06.2019 15:30

The movement of electrons between atoms is called an

Answers: 2

Answer

Physics, 22.06.2019 18:00

Avector of magnitude 2 cannot be added to a vector of magnitude 3 so that the magnitude of the resultant is a. zero b. 1 c. 3 d. 5 e. 7

Answers: 1

Answer

Physics, 22.06.2019 21:30

The three classes of rocks are sedimentary, metamorphic, and igneous. how are rocks classified into one of these three groups?