A current of 27 flows through a filament lamp when potential difference of Vis applied across How many electrons will move through the lamp in a time of 1 hour?

6.075×10²³ Electrons

Explanation:

From the question,

Q = it Equation 1

Where Q = quantity of charge, i = current, t = time.

Given: i = 27 A, t = 1 hours = 1×60×60 = 3600 seconds.

Substitute these values into equation 1

Q = 27×3600

Q = 97200 C.

If, one electron = 1.6×10⁻¹⁹ C,

Therefore, n electron = 97200×1/1.6×10⁻¹⁹ C.

n = 6.075×10²³ Electrons

which statement about this sum is true? −245+2.7

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