The diagram below shows the before and after image of a cannon-cannonball system. Initially, the cannon-cannonball system are combined as a single mass at a resting position. After collision, the cannon and cannonball are separated, each having their own velocities.
the 24.6 kg cannonball leaves the 1696.5 kg cannon at a velocity of 184.2 m/s, what is the magnitude of the recoil velocity of the cannon?

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

it's a b and

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr