toy car with a mass of 3.1 KG has 60 J of kinetic energy as he drives along the street part of a restaurant what is the velocity of the car (HELP pls)

6.22 m/s

Explanation:

m= 3.1 kg

k = 60 j

k = ( 1/2 ) mv^2

k = 0.5 × 3.1 × v^2 = 60

v^2 = 60 ÷ ( 0.5 × 3.1 )

v^2 = 38.7

v = 6.22 m/s

the bal will not change its velocity.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s