You have a hand-crank generator with a 100-turn coil (each turn having an area of 0.0350 m2), which can spin through a uniform magnetic field that has a magnitude of 0.0500 T. You can turn the crank at a maximum rate of 3 turns per second, but the hand crank is connected to the coil through a set of gears that makes the coil spin at a rate 6 times larger than the rate at which you turn the crank. What is the maximum emf you can expect to get out of this generator

Explanation:

Maximum emf produced = nωAB. where n is no of turns , A is area , B is magnetic field and ω is angular velocity .

n = 100 , A = .035 m²

B = .05 T

ω = 2π f , f is no of revolution per second by coil

= 2 x 3.14 x 6 x 3

= 113.04 rad /s

Maximum emf produced = 100 x 113.04 x .035 x .05

= 19.78  volt .

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