In the figure, a Mass m1 is connected to another mass m2 by a massless string over a frictionless pulley, when m1 slides on a surface by effecting of m2. M1= 2kg. M2= 1.5 kg

if the kinetic friction coefficient between m1 and the surface is 0.35

1- draw the free-body diagram of the forces acting on m1

2- calculate the acceleration of m1 on the surface.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Electricity and discharge