If the pelican was traveling 8.79 m/s but was only 2.7 m above the water, how far would the fish travel horizontally before hitting the water below?

6.52m

Explanation:

The horizontal distance travelled is known as its range. This is expressed as;

Range = u* √2H/g

u is the speed of the pelican

H is the maximum height

g is the acceleration due to gravity

Range = 8.79*√2(2.7)/9.8

Range = 8.79 * √5.4/9.8

range = 8.79*√0.5510

Range = 8.79*0.7423

Range = 6.52

Hence the fish will travel 6.52m before hitting the water below

temp rises, and expansion