Aforce of 25 newtons moves a box a distance of 4 meters in 5 seconds.
the work done on the box is nm, and the power is nm/s.

By definition, we have that the work done is given by:

Where,

F: force in the direction of displacement

d: displaced distance

Substituting values we have:

Then, the power is given by:

Where,

t: time

Substituting values we have:

The work done on the box is 100 Nm, and the power is 20 Nm/s.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j