A rock is thrown straight up with an initial speed of 15.5 m/s . It is caught at the same distance above the ground . How high does the ball rise? How long does the ball remain in the air?

Explanation:

Given;

initial velocity of the rock, u = 15.5 m/s

at maximum height the final velocity of the rock, v = 0

The height risen by the rock is calculated as follows;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u² / 2g

h = (15.5²) / (2 x 9.8)

h = 12.26 m

The time spent in air by the rock is known as time of flight, which is calculated as follows;

v = u - gt

0 = u - gt

gt = u

t = u/g

where;

t is the time to reach maximum height

t = 15.5 / 9.8

t = 1.58 s

Time of flight (time spent in air) is calculated as;

T = 2t

T = 2 x 1.58 s

T = 3.16 s.

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

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