If a plane lands on a runway and takes 10.4s to come to a complete stop at the end of the runway... how fast was it going as it started to land and what was its acceleration rate (this will be a negative number)? The distance traveled was 1400m

Explanation:

Given:

Δx = 1400 m

v = 0 m/s

t = 10.4 s

Find: v₀ and a

Δx = ½ (v + v₀) t

1400 m = ½ (0 m/s + v₀) (10.4 s)

v₀ = 269 m/s

Δx = vt − ½ at²

1400 m = (0 m/s) (10.4 s) − ½ a (10.4 s)²

a = -25.9 m/s²

-25.9 m/s²

Explanation:

Hope this helps

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

the right answer is 0.3 meters per second