For a 2050 kg satellite to have geosynchronous orbit it must have the same periodicity as the Earth which is 24 hours. What altitude above the Earth’s surface does the satellite orbit to
maintain geosynchronous orbit and what is its tangential velocity?
G = 6.67 x 10 -11 M earth = 5.98 x 10 24 kg r earth = 6.38 x 10 6 m

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car a and b are moving in opposite directions

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  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.