Please answer this question.

150.15 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 5 kg

Height (h) = 3 m

Kinetic energy (KE) =?

Next, we shall determine the velocity of the toy before hitting the ground. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Height (h) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

v² = u² + 2gh

v² = 0² + (2 × 10 × 3)

v² = 0 + 60

v² = 60

Take the square root of both side

v = √60

v = 7.75 m/s

Thus, the velocity of the toy before hitting the ground is 7.75 m/s.

Finally, we shall determine the kinetic energy of the toy before hitting the ground. This can be obtained as follow:

Mass (m) = 5 kg

Velocity (v) = 7.75 m/s.

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 5 × 7.75²

KE = 2.5 × 60.06

KE = 150.15 J

Thus, the kinetic energy of the toy before hitting the ground is 150.15 J

this means that the temperature of both substances will be equal

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever