The figure shows a velocity-versus-time graph for a particle moving along the x-axis. at t=0s, assume that x=0m. what is the particle's position at t=3.0s?

Using the velocity-time graph, the displacement can be calculated by the area under the velocity-time graph. At 3 seconds the total displacement is then equal to (4)(2) + (4 + 2)*1/2 = 11 m. Assuming that the starting point is at x = 0, then the particle at t=3s is at x=11 m.

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Sorry can’t u just tryna get points