What is the work done for a car of mass 900 kg to accelerate from 10 m/s to 20 m/s?

mass of car, m = 900 kg

initial velocity of car, u = 20 m/s

acceleration of car , a = 2m/s²

we have to find force required to acceleration this car and workdone after time t = 10s.

force = mass × acceleration.

so, force required to acceleration the car , F = 900kg × 2m/s² = 1800 N

workdone = force displacement.

so, we have to find displacement.

using formula, s = ut + 1/2 at²

= 20 × 10 + 1/2 × 2 × (10)²

= 200 + 100

= 300m

so, workdone = 1800 N × 300 m

= 540000 J

= 5.4 × 10^5 J

Explanation:

i hope you understand better

a straight line sloped

f is prop to m1xm2 double m1 double force