Physics, 19.10.2019 10:20 vanessa7676

Which statements describe rutherfords model of an atom? select all that apply.

[ ] the atom is mostly empty space.

[ ] the atom cannot be divided into smaller parts.

[ ] electrons orbit around the center of atom.

[ ] the atoms positive charge is located in the atoms nucles.

[ ] the electrons are located within the positive material of the nucleus.

[ ] electron cloud are region where electrons are like to be found.

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Answer from: ale1910

Answer;The atom is mostly empty space. Electrons orbit around the center of the atom. The atom's positive charge is located in the atom's nucleus.Explanation;According to the Rutherford's model an atom is mostly empty space, containing electrons which are negatively charged orbiting the nucleus that is fixed with a positive charge as a result of protons. An atom contains a tiny, dense, positively charged nucleus, where almost all the mass of an atom is concentrated. The nucleus is surrounded by energy levels which contains electrons that are negatively charged circulating around the nucleus.

Answer from: Rawr5801

The answers o he queston is 1 3 6

Answer from: Quest

Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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