3. What is the mass of a sample of alcohol (Specific heat = 2445 J/kg °C.) If it requires 4780 J of heat to raise the temperature by 5.43°C?
Given
Unknown Equation. Substitution
Solved

Q=mc∆tita.

4780J= m × 2445J/kg/°C × 5.43°C

4780J= m× 13276.35J/kg

m= 0.36Kg

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.